Use of variable speed AC Drives for speed control and Energy saving in Pulp &
Paper Abstract
This paper
describes use of "VARIABLE SPEED AC DRIVES" for Energy Saving by controlling
speed of squirrel Cage Induction motor for applications like Fans, Pumps &
Compressors in Pulp & Paper Industry.
Introduction
Energy Conservation Act, 2003 has identified Pulp & Paper Industry as one
of the key industries which need to implement energy savings, with an energy saving
potential as high as 15%. Pumps and fans are among the major consuming applications
in the paper making process. They are used to transport liquid/air by establishing
necessary draught. The volume of liquid/air needs to be varied as per the requirement
of process. Conventionally, a louver damper or throttling valve is provided in
the duct. The Pump/fan is always run at rated speed and volume of liquid/air is
controlled by increasing or decreasing the damper/throttling valve opening. As
the damper/throttling valve opening decreases, pressure drop across the same increases,
resulting in loss of some amount of energy across it.

The volume of air/gas/liquid can also be varied by changing the speed of Pump/fan
drive which will avoid damper/throttling valve losses. Speed of a Cage Induction
Motor can be varied by varying the supply frequency to the motor using a variable
speed drive.
Energy saving by speed control:
Fig. 1 shows typical performance characteristics of a centrifugal Pump/fan
(i) at rated speed & (ii) at reduced speed. Fig. 1 also shows typical system
curves (comprising of duct, fan etc.) (A) with damper control & (B) without
damper control. As air volume increases, the resistance caused by increasing turbulence
& friction in the fan/duct system results in rapid increase in the pressure
that must be developed by the Pump/fan. The pressure is proportional to square
of the flow (volume).

The
point of intersection of the system curve & the Pump/fan characteristics is
the operating point. With damper control employed, system will operate at point
"A" where volume requirement is "Q1" and corresponding pressure
developed in the duct will be "p1". Then power requirement of the Pump/fan
at operating point "A" will be "P1".
p1 * Q1
P1 =
-------------*10-3 KW
?F
Where ?F = Pump/fan efficiency
Similarly,
power requirement for operating point "B" for same volume "Q1"
with Pump/fan running at reduced speed i.e. with damper fully open will be "P2".
p2 * Q1
P2 = -------------*10-3 KW
?F
Therefore power saving achieved
by running the Pump/
fan at lower speed without damper control is equal to
"(P1-P2)" kW and is approximately equal to the area
of rectangle
" p1ABp2" (refer fig. 1).
Net power saving for the system is equal
to
( P1 - P2) * Q1
P3 = ----------------- *10-3 KW
?F * ?M
Where
?M = Motor efficiency
Total energy saved per annum when you run the Pump/
fan at lower speed is equal to
P3 * H kWHr
Where H = Annual run time
of Pump/fan in hours
In most of the cases, need for running the Pump/fan
at lower speed arises because of following reasons.
(i) Requirement to run
the process at lower than designed capacities
(ii) Cumulative safety margins
built during various design stages like duct design, Pump/fan design etc.
Hence
there is always a good potential for energy saving.
Estimation of energy
saving.
As an example, typical case is discussed here for estimating energy
saving
Relation between various system parameters
p ? Q2 where
p = Pressure, Q = Flow
Q ? N N = Motor Speed
p0 ? p*Q p0 = Motor Output
Power
As an example, typical case is discussed here for estimating energy
saving
Case Study
Motor Rating = 360 kW
Application = Pump
Sample
Calculation
Rated Parameters:
Rated flow: 231 M3/HR
Discharge Pressure: 37.27kg/cm2
Suction Pressure : 2.87 kg/cm2
Differential
Pressure: 34.4 kg/cm2
Pump efficiency: 72%
Present Running Parameters:
(As measured)
Flow: 280 MT/HR (Specific Gravity: 1.37) i.e. 204 M3/HR
Suction Pressure: 2.4 kg/cm2
Discharge Pressure: 42.5kg/cm2
Differential
Pressure: 40.1kg/cm2
Valve Opening: 24.1%
Pump efficiency at 204 M3/HR:
68%
Motor efficiency (assumed): 90%
Input Power to the Motor
P= (40.1*9.81*10)*(204/3600)/
(0.68*0.90)= 364kW
(The effect of static head is not considered, as it will
be same for the next case with variable speed drive) Ratio (Actual Flow / Rated
Flow) = 204/231= 0.8847
If the pump speed is reduced by the same proportion,using
variable speed AC Drive, the differential pressurewill reduce by square of the
same ratio. Hence, newdifferential pressure will be =34.4* (204/231) 2 = 26.92
kg/cm2
Revised Input Power to the Motor P' = (26.92*9.81*10)*(204/3600)/(0.68*0.90)=
244 kW Net Savings = 364-244= 120 kW If VSD losses are = 10 kW ( 96% efficiency),
Net Power saved is 110 kW With Unit Power rate of Rs 4.00, Total savings per year
will be 110*8760*4.0 = Rs 38.5 L
Note: It is assumed that the monitoring
points of suction & discharge pressures are such that the difference in these
two pressures eliminates the effect of static pressure. However, if actual static
head is given, the calculations can be refined further. Similarly, resistive drop
in the piping is neglected.
Key considerations for selection of inverter
A.
Temperature :-
The AC Drives are designed to operate at certain ambient
condition and they need to be derated if operated at higher ambient temperature.
Further, the design temperature should be "Site Maximum Ambient Temperature
plus additional minimum 5o C" to take care of temperature rise inside the
panel.
B. Overload Requirement in AC Drives :-
Overload i.e.
to deliver more than its capacity for a small duration is always desired to overcome
known & unknown loading conditions in the process. Specify the overload as
the application demands.
C. Harmonics :-
Like any other switching
device, AC Drives is one of the culprit of generating harmonics. Every AC Drive
addition will lead to increase in net Total Harmonic Distortion of the plant.
Possible
solutions to reduce harmonics generated by AC Drives are :
o Install
a DC or AC input reactor. This is must irrespective of ratings.
o Go for 12
pulse or higher input rectification configuration. The harmonics generated by
this system will be of the order of 12n 1. Thus, most predominant harmonics like
5th, 7th, 17th, 19th …… , are eliminated on the HV side of transformer.
Thus, 12-pulse rectification configuration drastically reduces harmonics current.
Hence for higher kW ratings 12-pulse rectification scheme helps in addressing
the problem of harmonics.
D. Is your AC Motor, General Purpose or Inverter
Grade ???
Most of us use general-purpose motors with inverters. When motor
to inverter panel cable distances are long (in excess of 30m), due to standing
wave phenomenon, high voltage spikes are generated at motor terminals. General-purpose
motors are not designed for such voltage spikes and results into premature burn
out / failure of their winding. To safe guard motor against this voltage spike,
appropriate protection device needs to be provided at output of the inverter e.g.
output reactor, sinusoidal filter.
Thus it is very important to install
output reactor or sinusoidal filter at the output of inverter.
Conclusion:
Use of Variable Speed Drive for Pump/fan results in significant energy saving.
Other benefits, which accrue, are precise speed control, less wear & tear
of mechanical system etc.
- Chirag Shah